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Build a two-stage probability tree, see every branch multiply out to a joint probability, and reverse the conditioning with Bayes' theorem.
Enter probabilities as decimals between 0 and 1, for example 0.25 for 25%.
P(Tests positive) = 0.09 + 0.18 = 0.27
P(Has condition | Tests positive) = 0.09 ÷ 0.27 = 0.33333
Out of 1,000 cases: about 90 are "Has condition and Tests positive", 10 are "Has condition and not Tests positive", 180 are "not Has condition and Tests positive", and 720 are "not Has condition and not Tests positive". Of the 270 with Tests positive, 90 also have Has condition, which is 33.33%.